the elevation of Denver Colorado is 13 times greater than that of waikapu. hawaii.the sum of their elevations is 5600 ft. find the elevation of each city

Let [tex]x[/tex] be the elevation of Denver and [tex]y[/tex] the elevation of Waikapu. Since the elevation of Denver is 13 times greater than the elevation of Waikapu, [tex]x=13y[/tex]. We also know that the sum of their elevations is 5600 ft, so [tex]x+y=5600[/tex]. We have now tow equations we can solve to find both altitudes:
[tex] \left \{ {{x=13y(1)} \atop {x+y=5600(2)}} \right. [/tex]
We can replace the value of [tex]x[/tex] from equation (1) in equation (2) to get:
[tex]13y+y=5600[/tex]
[tex]14y=5600[/tex]
[tex]y= \frac{5600}{14} [/tex]
[tex]y=400[/tex]
Now that we know the elevation of Waikapu, lets replace that value in equation (1) to get the elevation of Denver:
[tex]x=13(400)[/tex]
[tex]x=5200[/tex]

We can conclude that the elevation of Denver Colorado is 5200 ft, and the elevation of Waikapu Hawaii is 400 ft.