Suppose the number of dropped footballs for a wide receiver, over the course of a season, are normally distributed with a mean of 16 and a standard deviation of 2.What is the z-score for a wide receiver who dropped 13 footballs over the course of a season?−3−1.51.53

Answer:
The z-score would be -1.5.

Explanation:
The z-score shows how many standard deviations the number is from the mean.
So to find this answer you start by finding how far the number is from the mean.
13-16 = -3. So, the number is 3 less than the mean,

Then you must find how many standard deviations that is away.
So, to find this you must divide by the standard deviation.
z-score = [tex] \frac{-3}{2} [/tex] = -1.5.