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How many numbers greater than 3,000,000 can be formed from permutations of 1, 2, 2, 4, 6, 6, 6?
4 months ago
Q:
How many numbers greater than 3,000,000 can be formed from permutations of 1, 2, 2, 4, 6, 6, 6?
Accepted Solution
A:
Let's look at the problem;
There are 7 digits in 3,000,000 and 7 given digits. However, the numbers starting with either 6 or 4 will be greater than 3,000,000.
If the first digit is 4, 6!/(2!3!) = 60 <--- I knew that there would be 3 repetitions of 6 and 2 repetitions of 2, which I divided away.
If the first digit is 6, 6!/(2!2!)= 180 <-- repeat as above
The first digit can be 6 or 4, therefore, we add the possible ways.
60+180=240 possible permutations
Hope I helped :)