MATH SOLVE

10 months ago

Q:
# Help with 7, 9, 15, & 17 please

Accepted Solution

A:

let d to be the distance:

7. A(2,3), B(6,3), C(2,7)

dᵃᵇ= √((2-6)²+(3-3)²)

dᵃᵇ= 4

dᵃc=√((2-2)²+(7-3)²)= 4

dᵇc=√((2-6)²+(7-3)²)=0

a²+b²=c²

4²+4²=32

so it is a right triangle.

9.

A(1,9), B(4,8), C(2,5)

d AB= √((8-4)²+(4-9)²)=√41

d BC=√((2-4)²+(5-8)²)=√13

d AC= √((2-1)²+(5-9)²)=√17

(√17)²+(√13)²=(√41)²

17+13=41

30≠41

so it is not a right triangle.

15.

Add the interior opposite angles together to get the exterior angle:

∠2 = 75+64= 139

17.

24+2x+8=3x+6

2x+32=3x+6

x+6=26

x=20

so the exterior angle is (3*20+6)=66

genius

7. A(2,3), B(6,3), C(2,7)

dᵃᵇ= √((2-6)²+(3-3)²)

dᵃᵇ= 4

dᵃc=√((2-2)²+(7-3)²)= 4

dᵇc=√((2-6)²+(7-3)²)=0

a²+b²=c²

4²+4²=32

so it is a right triangle.

9.

A(1,9), B(4,8), C(2,5)

d AB= √((8-4)²+(4-9)²)=√41

d BC=√((2-4)²+(5-8)²)=√13

d AC= √((2-1)²+(5-9)²)=√17

(√17)²+(√13)²=(√41)²

17+13=41

30≠41

so it is not a right triangle.

15.

Add the interior opposite angles together to get the exterior angle:

∠2 = 75+64= 139

17.

24+2x+8=3x+6

2x+32=3x+6

x+6=26

x=20

so the exterior angle is (3*20+6)=66

genius