Given the domain {-4, 0, 5}, what is the range for the relation 12x + 6y = 24? A. {2, 4, 9} B. {12, 4, -6} C. {-4, 4, 14} D. {-12, -4, 6}

The range is: B. {12, 4, -6}Step-by-step explanation:Given12x + 6y = 24Here x is the input and y is the outputSo,Replacing y with f(x)[tex]12x +6f(x) = 24\\6f(x) = 24 - 12x\\\frac{6f(x)}{6} = \frac{24-12x}{6}\\f(x) = \frac{24-12x}{6}[/tex]Domain =  {-4, 0, 5},We will put the elements of domain, one by one, to find range[tex]f(-4) = \frac{24-12(-4)}{6}\\=\frac{24+48}{6}\\= \frac{72}{6}\\=12\\\\f(0) = \frac{24-12(0)}{6}\\=\frac{24}{6}\\= 4\\\\f(5) = \frac{24-12(5)}{6}\\=\frac{24-60}{6}\\=\frac{-36}{6}\\=-6[/tex]Hence,The range is: B. {12, 4, -6}Keywords: Range, Domain, functionsLearn more about functions at:brainly.com/question/3375830brainly.com/question/3398261#LearnwithBrainly