g(x) = x3 + 6x2 + 12x + 8 Determine the function’s value when x = −1. g(−1) = −3 g(−1) = 0 g(−1) = 1 g(−1) = 27

The correct answer is that g(-1) = 1.

To do this problem, we have to plug in -1 for x and evaluate the expression.

g(-1) = x^3 + 6x^2 + 12x + 8

(-1)^3 + 6(-1)^2 + 12(-1) + 8

-1 + 6 -12 + 8

1