find the rectangular coordinates of the point (-4, pi/3)

Answer:[tex]\texttt{The rectangular coordinates of the point (-4, pi/3)}=(-2,-2\sqrt{3})[/tex]Step-by-step explanation:Conversion of parametric form of ( r , θ ) to rectangular coordinate can be done by using the formula ( rcosθ , rsinθ ).Here we need to convert (-4, pi/3) in to rectangular coordinate form.Which can be converted to rectangular coordinate form as          [tex]\left ( -4cos\left ( \frac{\pi}{3} \right),-4sin\left ( \frac{\pi}{3} \right)\right )=\left ( -4\times \left ( \frac{1}{2} \right),-4\times \left ( \frac{\sqrt{3}}{2} \right)\right )=(-2,-2\sqrt{3})[/tex][tex]\texttt{The rectangular coordinates of the point (-4, pi/3)}=(-2,-2\sqrt{3})[/tex]