Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side sides are 5.

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
      = 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
      = √(5² - 1²)
      = √(25 - 1)
      = √24
      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

[tex]A = \frac{(AB + CD)DH}{2} [/tex]

A = (7 + 5) × 2√6 ÷ 2
   = 12√6

The area of the regular trapezoid is 12√6 square units.