A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
Accepted Solution
A:
L x W = 60 2(L + W) = 32 L + W = 16 L = 16 - W
substitute L = 16 - W into L x W = 60 L x W = 60 (16 - W) x W = 60 16W -W^2 = 60 W^2 - 16W + 60 = 0 (W - 6)(W - 10) = 0 W - 6 = 0; W = 6 W - 10 = 0; W = 10