A human society has 73 dogs and cats to be adopted. the number of cats is 10 more than twice the number of dogs. Write a system of linear equations that represent this situation. How many of each animal is up for adoption?
Accepted Solution
A:
Total: 73 dogs: x cats: 2x+10
2x+10+x=73 3x+10=73 3x=63 x=21
dogs: x dogs: 21
cats: 2x+10 cats: 52
Check answer: cats+dogs=73 52+21=73
There's no need for a system of linear equations if you were to solve a real life problem like this. In calculus, they don't give a rat about HOW you get your answer to an easy algebra 1 equation, as long as you used one of the correct methods and got the right answer.