A funnel is made up of a partial cone and a cylinder as shown in the figure. The maximum amount of liquid that can be in the funnel at any given time is 16.59375 cubic centimeters. Given this information, what is the volume of the partial cone that makes up the top part of the funnel?

The volume of the partial cone is the volume of the entire funnel minus the volume of the cylindrical part.

The volume of a cylinder is given by:

[tex]V=\pi r^2h[/tex]
where: r is the radius of the cylinder and h is the height of the cylinder.

Given that the cylindrical part of the funnel has a height of 1.5 cm and a diameter of 1.5 cm, thus the radius is 1.5 / 2 = 0.75 cm and the volume is given by:

[tex]V=\pi(0.75)^2(1.5)=0.84375\pi=2.65072cm^3[/tex]

Therefore, the volume of the partial cone is given by 16.59375 - 2.65072 = 13.94303 cubic cm.