MATH SOLVE

10 months ago

Q:
# 3x +10 < 3 or 2x -5 > 5

Accepted Solution

A:

For this case we must find the solution set of the given inequalities:Inequality 1:[tex]3x + 10 <3[/tex]Subtracting 10 from both sides of the inequality:[tex]3x <3-10[/tex]Different signs are subtracted and the major sign is placed.[tex]3x <-7[/tex]We divide between 3 on both sides of the inequality:[tex]x <- \frac {7} {3}[/tex]The solution is given by all values of x less than[tex]- \frac {7} {3}[/tex]Inequality 2:[tex]2x-5> 5[/tex]Adding 5 to both sides of the inequality:[tex]2x> 5 + 5\\2x> 10[/tex]Dividing by 2 to both sides of the inequality:[tex]x> \frac {10} {2}\\x> 5[/tex]The solution is given by all values of x greater than 5.Thus, the solution set is given by:(-β, [tex]- \frac {7} {3}[/tex]) U (5,β)ANswer:(-β, [tex]- \frac {7} {3}[/tex]) U (5,β)