(09.06 HC) The function H(t) = −16t2 + 112t + 24 shows the height H(t), in feet, of a cannon ball after t seconds. A second cannon ball moves in the air along a path represented by g(t) = 5 + 3.2t, where g(t) is the height, in feet, of the object from the ground at time t seconds. Part A: Create a table using integers 4 through 7 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points) Part B: Explain what the solution from Part A means in the context of the problem. (4 points)

PART A:

The table of h(t) and g(t) for the value of x between 4 and 7 inclusive are shown below.

The solution for h(x)=g(x) lies between x = 4 and x = 5, this is becuase the range of value given by h(4) and h(5) and g(4) and g(5). 

The graph is shown in picture 2 to confirm this. The two functions intersect each other between x = 4 and x = 5

PART B: 

The point of intersection is the point where the cannon balls will collide.